1/3+3/4:x=-3
3/4:x=-3-1/3
3/4:x=-10/3
x=3/4:-10/3
x=-9/40
bài này rất cơ bản mà bạn, bạn chỉ cần vận dụng các kiến thức về tìm x là bạn giải dc ngay
1/3 + 3/4 : x = -3
1/3 + (3/4 : x) = -3
3/4 : x = -3 - 1/3
3/4 - x = -10/3
x = -10/3 + 3/4
x = -31/12
\(\Leftrightarrow\dfrac{1}{3}+\dfrac{3}{4}.\dfrac{1}{x}=-3\\ \Leftrightarrow\dfrac{1}{3}+\dfrac{3}{4x}=-3\\ \Leftrightarrow\dfrac{3}{4x}=-3-\dfrac{1}{3}\\ \Leftrightarrow\dfrac{3}{4x}=\dfrac{-10}{3}\\ \Leftrightarrow4x=3:\dfrac{-10}{3}\\ \Leftrightarrow4x=\dfrac{-9}{10}\\ \Leftrightarrow x=\dfrac{-9}{10}:4\\ \Leftrightarrow x=\dfrac{-9}{40}\)
$\frac{1}{3}+\frac{3}{4}:x=-3$
$\Rightarrow \frac{3}{4}:x=-3-\frac{1}{3}$
$\Rightarrow \frac{3}{4}:x=-\frac{10}{3}$
$\Rightarrow x=-\frac{2}{5}$
\(\dfrac{1}{3}+\dfrac{3}{4}:x\)\(=-3\)
\(\dfrac{3}{4}:x\)=\(-3-\dfrac{1}{3}\)
\(\dfrac{3}{4}:x\)=\(\dfrac{-10}{3}\)
\(x=\dfrac{3}{4}:\dfrac{-10}{3}\)
\(x=\dfrac{-9}{40}\)
Vậy \(x=\dfrac{-9}{40}\)
Ta có: \(\dfrac{1}{3}+\dfrac{3}{4}:x=-3\)
\(\Rightarrow\dfrac{3}{4}:x=\left(-3\right)-\dfrac{1}{3}\)
\(\Rightarrow\dfrac{3}{4}:x=\left(-3\right)+\left(-\dfrac{1}{3}\right)\)
\(\Rightarrow\dfrac{3}{4}:x=\left(-\dfrac{9}{3}\right)+\left(-\dfrac{1}{3}\right)\)
\(\Rightarrow\dfrac{3}{4}:x=-\dfrac{10}{3}\)
\(\Rightarrow x=\dfrac{3}{4}:\left(-\dfrac{10}{3}\right)\)
\(\Rightarrow x=\dfrac{3}{4}.\left(-\dfrac{3}{10}\right)\)
\(\Rightarrow x=\dfrac{-9}{40}\)
Vậy \(x=\dfrac{-9}{40}\)
