\(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{2}\right)^{10}\)
\(\Leftrightarrow\dfrac{1}{16^x}=\dfrac{1}{2^{10}}\)
\(\Leftrightarrow\dfrac{1}{2^{4x}}=\dfrac{1}{2^{10}}\)
\(\Leftrightarrow4x=10\Leftrightarrow x=\dfrac{5}{2}\)
\(\left(\dfrac{1}{16}\right)^x=\left(\dfrac{1}{2}\right)^{10}\)
\(\Leftrightarrow\dfrac{1}{16^x}=\dfrac{1}{2^{10}}\)
\(\Leftrightarrow\dfrac{1}{2^{4x}}=\dfrac{1}{2^{10}}\)
\(\Leftrightarrow4x=10\Leftrightarrow x=\dfrac{5}{2}\)
tìm x biết (1/16)^x+2=(1/32)^6
bài 1 tìm các số nguyên x,y biết a)2^x=8
b) 3^4=27
c)(-1,2).x=(-1,2)^4
d)x:(-3/4)=(-3/4)^2
e)(x+1)^3=-125
f)(x-2)^3=64
bài 2 tìm các số nguyên x,y biết
a)(x-1,2)^2=4
d)(x-1,5)^2=9
e)(x-2)^3=64
`(x+1)/16-(2x-1)/8=(-x-8)/2`
Tìm x:
a, (\(\dfrac{1}{3}\)+ \(\dfrac{1}{6}\)) .\(2^x\)+ \(2^{x+1}\)= \(2^{12}\)+\(2^{10}\)
b, (\(\dfrac{1}{2}\)- \(\dfrac{1}{6}\)) . \(3^x\)+ \(3^{x+2}\)= \(3^{16}\)+\(3^{13}\)
(1/2)^2.x=(1/2)^5
(-1/3)^3.x=(1/81)
(2x-3)^2=16
Tìm x,y biết
a) \(x^4+\left(y-\frac{1}{10}\right)^6=0\)
b) (\(\frac{1}{2}x-5\))^20+(\(y^2-\frac{1}{4}\))^10\(\le\)0
1: Tính : \(\dfrac{\left(\dfrac{2}{5}\right)^7.5^7+\left(\dfrac{9}{4}\right)^3:\left(\dfrac{3}{16}\right)^3}{2^7.5^2+512}\) 2 . Tìm x biết :\(\left(5.x+1\right)^2=\dfrac{36}{49}\)
1. Tìm x \(\in\) Q, biết
a) (x-\(\dfrac{1}{3}\))\(^2\) = 0
b) (x+\(\dfrac{1}{2}\))\(^2\) = \(\dfrac{1}{16}\)
c) (2x-1)\(^3\) = 8
Giúp mk vs
1.Tìm x, biết:
a. 2x ; b. 5x c. 3x : 35 d. \(\dfrac{16}{2^x}=2\) e. 8x : 2x f. 2x . 3x = 36 g. \(\dfrac{\left(-3\right)^n}{81}=-27\)