Tìm x biết: 10 - 2 . (x + 3) = 5 . (x - 2)
theo đề ta có:
10 - 2 . (x + 3) = 5 . (x - 2)
=> \(\dfrac{x+3}{x-2}=\dfrac{5}{10-2}\)
=> \(\dfrac{x+3}{x-2}=\dfrac{5}{8}\)
=> x+3 = 5
=> x= 2
và x-2= 8
=> x= 10
\(10-2\left(x+3\right)=5\left(x-2\right)\\ \Leftrightarrow10-\left(2x+6\right)=5x-10\\ \Leftrightarrow10-2x-6=5x-10\\ \Leftrightarrow7x=10-6+10\\ \Leftrightarrow7x=14\\ \Leftrightarrow x=2\)