Question

Tìm x: a)x÷144-23=121 b)(2x+1)×2907=8721 c)(4x-16)÷1905=60

Answer 1

a) \(x:144-23=121\)

\(\Rightarrow x:144=121+23\)

\(\Rightarrow x:144=144\)

\(\Rightarrow x=20736\)

b) \(\left(2x+1\right).2907=8721\)

\(\Rightarrow2x+1=3\)

\(\Rightarrow2x=2\Rightarrow x=1\)

c) \(\left(4x-16\right):1905=60\)

\(\Rightarrow4x-16=114300\)

\(\Rightarrow4x=114316\)

\(\Rightarrow x=28579\)

 

Answer 2

`x : 144 -23=121`

`x : 144 = 121 + 23`

`x:144 = 144`

`x=144xx144`

`x=20736`

___________________________

`(2x+1)xx2907 = 8721`

`2x +1 = 8721 : 2907`

`2x+1=3`

`2x=3-1`

`2x=2`

`=> x = 1`

______________________________

`(4x-16):1905 = 60`

`4x-16 = 60 xx 1905`

`4x-16 = 114300`

`4x = 114300 + 16`

`4x=114316`

`x=114316:4`

`x=28579`

Answer 3

\(a,\\ x:144-23=121\\ x:144=121+23\\ x:144=144\\ x=144:144\\ x=1\\ b,\\ \left(2x+1\right)\cdot2907=8721\\ 2x+1=8721:2907\\ 2x+1=3\\ 2x=3-1\\ 2x=2\\ x=2:2\\ x=1\\ c,\\ \left(4x-16\right):1905=60\\ 4x-16=60\cdot1905\\ 4x-16=114300\\ 4x=114300+16\\ 4x=114316\\ x=114316:4\\ x=28579\)