Question

Tìm x :

a) x ( x - 1 ) - x^2 + 2x = 5

b) 4x ( 3x + 2 ) - 6x ( 2x + 5 ) + 21 ( x - 1 ) = 0

c) 2x( x + 1) - x^2 ( x + 2 ) + x^3 - x + 4 = 0

Answer 1

a) \(x\left(x-1\right)-x^2+2x=5\)

\(\Leftrightarrow x^2-x-x^2+2x=5\)

\(\Leftrightarrow x=5\)

b) \(4x\left(3x+2\right)-6x\left(2x+5\right)+21\left(x-1\right)=0\)

\(\Leftrightarrow12x^2+8x-12x^2-30x+21x-21=0\)

\(\Leftrightarrow-x=21\)

\(\Leftrightarrow x=-21\)

c) \(2x\left(x+1\right)-x^2\left(x+2\right)+x^3-x+4=0\)

\(\Leftrightarrow2x^2+2x-x^3-2x^2+x^3-x+4=0\)

\(\Leftrightarrow x=-4\)

Answer 2

a) x ( x - 1 ) - x^2 + 2x = 5

=>x²-x-x²+2x=5

=>-x+2x=5

=>x=5

b) 4x ( 3x + 2 ) - 6x ( 2x + 5 ) + 21 ( x - 1 ) = 0

=>12x²+8x-12x²-30x-21+21x=0

=>-x-21=0

=>x=-21

c) 2x( x + 1) - x^2 ( x + 2 ) + x^3 - x + 4 = 0

=>2x²+2x-x³-2x²+x³-x+4=0

=>x+4=0

=>x=-4