\(\frac{2}{3}x\) - \(\frac{1}{5}\) = \(\frac{-2}{3}\)
\(\frac{2}{3}x\) = \(\frac{-2}{3}\) + \(\frac{1}{5}\)
\(\frac{2}{3}x\) = \(\frac{-10}{15}\) +\(\frac{3}{15}\)
\(\frac{2}{3}x\) = \(\frac{-7}{15}\)
\(x\) = \(\frac{-7}{15}\) : \(\frac{2}{3}\)
\(x\) = \(\frac{-7}{15}\). \(\frac{3}{2}\)
\(x\) = \(\frac{-7}{10}\)
Vậy \(x\) = \(\frac{-7}{10}\)