ƯCLN (28,39,35)=1
ƯCLN(48,60,120)=12
ƯCLN(30,75,135)=15
`a, (28, 39, 35) = 1`.
`b, (48, 60, 120) = 12`.
`c, (30,75, 135) = 15`
`ƯCLN N(28,39,35)=1`
`ƯCLN N(48,60,120)=12`
`ƯCLN N(30,75,135)=15`
ta có :
`28 = 2^2 xx 7`
`39 = 3 xx 13`
`35 = 5 xx 7`
`=> ƯCNNN(28 ; 39 ; 35) = 1`
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ta có :
`48 = 2^4 xx 3`
`60 = 2^2 xx 3 xx 5`
`120 = 2^3 xx 3 xx 5`
`=> ƯCNNN(48 ; 60 ; 120) = 2^2 xx 3 = 12`
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ta có :
`30 = 2 xx 3 xx 5`
`75 = 3 xx 5^2`
`135 = 3^3 xx 5`
`=> ƯCNNN( 30 ; 75 ; 135) = 3 xx 5 = 15`