\(d\left(O;d\right)=\dfrac{\left|\left(m-2\right)\cdot0+\left(-1\right)\cdot0+3\right|}{\sqrt{\left(m-2\right)^2+1}}=\dfrac{3}{\sqrt{\left(m-2\right)^2+1}}\)
Để d=1 thì \(\sqrt{\left(m-2\right)^2+1}=3\)
=>(m-2)^2+1=9
=>(m-2)^2=8
=>\(m=\pm2\sqrt{2}+2\)