Ta có :x2+y2+6y+5=0
\(\Leftrightarrow\) x2+(y2+6y+9)-4 =0
\(\Leftrightarrow\) x2 + (y+3)2-2 =0
\(\Leftrightarrow\) x2 +(y+3+2)(y+3-2)=0
\(\Leftrightarrow\) x2+(y+5)(y+1)=0
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}x^2=0\\\left(y+5\right)^2=0\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}x^2=0\\\left(y+1\right)^2=0\end{matrix}\right.\)
\(\Leftrightarrow\) \(\left\{{}\begin{matrix}x=0\\y=-5\end{matrix}\right.\) hoặc \(\left\{{}\begin{matrix}x=0\\y=-1\end{matrix}\right.\)
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