x2 +2x +1 -1 -2y-y2 =2011
(x+1)2 -(y+1)2 =2011
(x-y)(x+y+2) =2011
\(\left\{{}\begin{matrix}x-y=2011\\x+y+2=1\end{matrix}\right.\) (th1)
\(\left\{{}\begin{matrix}x-y=1\\x+y+2=2011\end{matrix}\right.\) (th2)
\(\left\{{}\begin{matrix}x-y=-1\\x+y+2=-2011\end{matrix}\right.\) (TH3)
\(\left\{{}\begin{matrix}x-y=-2011\\x+y+2=-1\end{matrix}\right.\) (th4)
roi tu giai ra nhen ban lay so nguyen bo phan so 
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