(2x+1)(y-3)=12
=>(2x+1)(y-3)=1.12
=>2x+1=1
y-3=12
=>x=0
y=15
(2x+1)(y-3)=12
\(\Rightarrow\)2x+1 và y-3 \(\in\)Ư(12)=\(\left\{\pm1;\pm2;\pm3;\pm4;\pm6;\pm12\right\}\)
2x+1 | 1 | -1 | 2 | -2 | 3 | -3 |
y-3 | 12 | -12 | 6 | -6 | 4 | -4 |
x | 0 | -1 | \(\frac{1}{2}\) | \(\frac{-3}{2}\) | 1 | -2 |
y | 15 | -9 | 9 | 3 | 7 | -1 |