\(x\ne2\)
\(A=\frac{4x-6}{x-2}=\frac{4x-8+2}{x-2}=4+\frac{2}{x-2}\)
Để A nguyên \(\Rightarrow\frac{2}{x-2}\) nguyên \(\Rightarrow2⋮\left(x-2\right)\)
\(\Rightarrow x-2=Ư\left(2\right)=\left\{-2;-1;1;2\right\}\)
\(x-2=-2\Rightarrow x=0\)
\(x-2=-1\Rightarrow x=1\)
\(x-2=1\Rightarrow x=3\)
\(x-2=2\Rightarrow x=4\)