Ta có:
\(\dfrac{n+5}{2n-1}=\dfrac{2n+10}{2n-1}=\dfrac{2n-1+11}{2n-1}=1+\dfrac{11}{2n-1}\)
Để \(n+5\) chia hết cho \(2n-1\) thì
\(11\) chia hết cho \(2n-1\)
\(\Rightarrow2n-1\inƯ\left(11\right)\)
\(\Rightarrow2n-1\in\left\{-11;-1;1;11\right\}\)
\(\Rightarrow2n\in\left\{-10;0;2;12\right\}\)
\(\Rightarrow n\in\left\{-5;0;1;6\right\}\)
Vậy............
Chúc bạn học tốt!!!