\(\left(2x+5\right)\left(3-x\right)=0\)
\(\Rightarrow\left[{}\begin{matrix}x=-\dfrac{5}{2}\\x=3\end{matrix}\right.\)
(2x+5).(3-x) = 0
=>\(\left[{}\begin{matrix}2x+5=0\\=>x=\dfrac{-5}{2}\end{matrix}\right.\)
=> \(\left[{}\begin{matrix}3-x=0\\=>x=3\end{matrix}\right.\)