\(x^3+x^2+x+1=0\)
\(\Leftrightarrow\left(x^3+x^2\right)+\left(x+1\right)=0\)
\(\Leftrightarrow x^2\left(x+1\right)+\left(x+1\right)=0\)
\(\Leftrightarrow\left(x+1\right)\left(x^2+1\right)=0\)
Dễ thấy: \(x^2+1\ge1>0\forall x\) (vô nghiệm)
\(\Rightarrow x+1=0\Rightarrow x=-1\)