a) Đặt f(x)=0
\(\Leftrightarrow-5x-4=0\)
\(\Leftrightarrow-5x=4\)
hay \(x=-\frac{4}{5}\)
Vậy: \(S=\left\{-\frac{4}{5}\right\}\)
b) Đặt F(x)=0
\(\Leftrightarrow13-3x=0\)
\(\Leftrightarrow3x=13\)
hay \(x=\frac{13}{3}\)
Vậy: \(S=\left\{\frac{13}{3}\right\}\)
c) Đặt h(x)=0
\(\Leftrightarrow-15+5x=0\)
\(\Leftrightarrow5x=15\)
hay x=3
Vậy: S={3}
d) Đặt k(x)=0
\(\Leftrightarrow\frac{4}{5}x+\frac{16}{25}=0\)
\(\Leftrightarrow\frac{4}{5}x=-\frac{16}{25}\)
hay \(x=-\frac{16}{25}:\frac{4}{5}=\frac{-16}{25}\cdot\frac{5}{4}=-\frac{80}{100}=-\frac{4}{5}\)
Vậy: \(S=\left\{-\frac{4}{5}\right\}\)