Question

Tìm n biết

8 chia hết cho n-3

Answer 1

Ta có: \(8⋮\left(n-3\right)\\ =>\left(n-3\right)\inƯ\left(8\right)=\left\{\pm1;\pm2;\pm4;\pm8\right\}\\ \)

Lập bảng:

n-3	1	2	4	8	-1	-2	-4	-8
n	4	5	7	11	2	1	-1	-5

=> \(n\in\left\{\pm1;2;4;\pm5;7;11\right\}\)

Answer 2

Vì \(8⋮n-3\Rightarrow n-3\inƯ\left(8\right)=\left\{\pm1;\pm2\pm;4\pm8\right\}\)

Ta có bảng sau:

\(n-3\)	\(1\)	\(-1\)	\(2\)	\(-2\)	\(4\)	\(-4\)	\(8\)	\(-8\)
\(n\)	\(4\)	\(2\)	\(5\)	\(1\)	\(7\)	\(-1\)	\(11\)	\(-5\)

Vậy \(n\in\left\{\pm1;2;4;\pm5;7;11\right\}\)

Answer 3

\(8⋮n-3\)

Vì \(8⋮n-3\) nên \(n-3\inƯ\left(8\right)\)

\(\Rightarrow n-3\in\left\{-8;-4;-2;-1;1;2;4;8\right\}\)

\(\Rightarrow n\in-5;-1;1;2;4;5;7;11\)

Chúc bạn học tốt!!!