\(1-2sin^2x-2sinx-m+1=0\)
\(\Leftrightarrow-2sin^2x-2sinx+2=m\)
Xét \(f\left(x\right)=-2sin^2x-2sinx+2\)
\(f\left(x\right)=-2\left(sinx+\frac{1}{2}\right)^2+\frac{5}{2}\le\frac{5}{2}\)
\(f\left(x\right)=-2sin^2x-2sinx+4-2=2\left(1-sinx\right)\left(sinx+2\right)-2\ge-2\)
\(\Rightarrow-2\le m\le\frac{5}{2}\) thì pt có nghiệm