Xét trên đoạn \(\left[-2;2\right]\) ta có:\(f\left(x\right)=3x^2+6x-9\)
\(f\left(x\right)=0\Leftrightarrow\left[\begin{matrix}x=-3\left(l\right)\\x=1\end{matrix}\right.\)
Ta có:\(f\left(-2\right)=23,f\left(1\right)=-4,f\left(2\right)=3\)
Vậy \(max\)f =(x) = \(f\left(-2\right)=23,min\) f(x)= \(f\left(1\right)=4\)[-2;2]