\(\left|x-1,5\right|+\left|2,5+x\right|=0\)
\(\Rightarrow\left|x-1,5\right|\ge0\)
\(\Rightarrow\left|2,5-x\right|\ge0\)
Nên : + ) \(x-1,5=0\)
\(\Leftrightarrow x=1,5\)
+ ) \(2,5-x=0\)
\(\Leftrightarrow x=2,5\)
Ta có : \(1,5+2,5\ne0\)
Vậy x vô nghiệm .