Ta có: \(\sqrt{6-x^2}\le\sqrt{6}\)
\(\Rightarrow-2\sqrt{6-x^2}\ge-2\sqrt{6}\)
\(\Rightarrow5-2\sqrt{6-x^2}\ge5-2\sqrt{6}\)
\(\Rightarrow A=\dfrac{1}{5-2\sqrt{6-x^2}}\le\dfrac{1}{5-2\sqrt{6}}=5+2\sqrt{6}\)
\(\Rightarrow Max_A=5+2\sqrt{6}\Leftrightarrow x=0\)