\(\lim\limits\left(u_n\right)=\lim\limits\frac{\sqrt{4n^2-1}+\sqrt[3]{8n^3+2n^2-3}}{\sqrt{16n^2+4n}-\sqrt[4]{n^4+1}}=\lim\limits\frac{\sqrt{4-\frac{1}{n^2}}+\sqrt[3]{8+\frac{2}{n}-\frac{3}{n^3}}}{\sqrt{16+\frac{4}{n}}-\sqrt[4]{1+\frac{1}{n^4}}}=\frac{\sqrt{4}+\sqrt[3]{8}}{\sqrt{16}-\sqrt[4]{1}}=\frac{4}{3}\)