\(P=\left(x^2-4x-5\right)\left(x^2-4x-5-14\right)+49\)
Đặt \(x^2-4x-5=a\)
\(P=a\left(a-14\right)+49=a^2-14a+49=\left(a-7\right)^2\ge0\)
\(\Rightarrow P_{min}=0\) khi \(a=7\Rightarrow x^2-4x-5=7\Rightarrow\left[{}\begin{matrix}x=6\\x=-2\end{matrix}\right.\)