Ta có : \(-x+\sqrt{x}=-\left(x-\sqrt{x}+\frac{1}{4}\right)+\frac{1}{4}=-\left(\sqrt{x}-\frac{1}{2}\right)^2+\frac{1}{4}\le\frac{1}{4}\)
\(\Rightarrow f\left(x\right)=3^{-x+\sqrt{x}}\le3^{\frac{1}{4}}=\sqrt[4]{3}\Rightarrow\) Max \(f\left(x\right)=\sqrt[4]{3}\) khi \(x=\frac{1}{4}\)
Không có giá trị Min