ĐKXĐ: ...
\(A\le\sqrt{2\left(x-1+y-2\right)}=\sqrt{2\left(x+y-3\right)}=\sqrt{2}\)
\(A_{max}=\sqrt{2}\) khi \(\left\{{}\begin{matrix}x-1=y-2\\x+y=4\end{matrix}\right.\) \(\Rightarrow\left\{{}\begin{matrix}y=\frac{5}{2}\\x=\frac{3}{2}\end{matrix}\right.\)