Để \(P\in Z\) thì :
\(2n-1⋮n-1\)
Mà \(n-1⋮n-1\)
\(\Leftrightarrow\left\{{}\begin{matrix}2n-1⋮n-1\\2n-2⋮n-1\end{matrix}\right.\)
\(\Leftrightarrow1⋮n-1\)
\(\Leftrightarrow n-1\inƯ\left(1\right)\)
\(\Leftrightarrow\left[{}\begin{matrix}n-1=1\\n-1=-1\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}n=2\\n=0\end{matrix}\right.\)
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