\(\dfrac{x}{2}+\dfrac{x}{y}-\dfrac{3}{2}=\dfrac{10}{y}\)
\(\dfrac{x-3}{2}=\dfrac{10-x}{y}\)
\(\Rightarrow\left(x-3\right)y=2\left(10-x\right)\)
\(\Rightarrow xy-3y-20+2x=0\)
\(\Rightarrow x\left(y+2\right)-3\left(y+2\right)-14=0\)
\(\Rightarrow\left(x-3\right)\left(y+2\right)=14\)
Lập bảng là ra nha bn