\(A=\frac{1-x^3}{x-2}=-x^2-2x-4-\frac{7}{x-2}\)
Để A nguyên \(\Rightarrow\frac{7}{x-2}\) nguyên \(\Rightarrow x-2=Ư\left(7\right)=\left\{-7;-1;1;7\right\}\)
\(x-2=-7\Rightarrow x=-5\)
\(x-2=-1\Rightarrow x=1\)
\(x-2=1\Rightarrow x=3\)
\(x-2=7\Rightarrow x=9\)