\(10\dfrac{1}{4}:\left(-\dfrac{3}{4}\right)-8\dfrac{1}{4}:\left(-\dfrac{3}{5}\right)\)
= \(\dfrac{41}{4}:\left(-\dfrac{3}{4}\right)-\dfrac{33}{4}:\left(-\dfrac{3}{5}\right)\)
= \(\dfrac{41}{4}.\dfrac{\left(-4\right)}{3}-\dfrac{33}{4}.\dfrac{\left(-5\right)}{3}\)
=\(\dfrac{-84}{12}-\dfrac{\left(-165\right)}{12}\)
= \(\dfrac{-84}{12}+\dfrac{165}{12}\)
=\(\dfrac{-84+165}{12}\)
=\(\dfrac{81}{12}\)
=\(\dfrac{27}{4}\)