Giải:
\(5\dfrac{27}{5}+\dfrac{27}{23}+0,5-\dfrac{5}{27}+\dfrac{16}{23}\)
\(=5+\dfrac{27}{5}+\dfrac{27}{23}+0,5-\dfrac{5}{27}+\dfrac{16}{23}\)
\(=5+\dfrac{27}{5}+\dfrac{43}{23}+\dfrac{1}{2}-\dfrac{5}{27}\)
\(=\dfrac{52}{5}+\dfrac{43}{23}+\dfrac{1}{2}-\dfrac{5}{27}\)
\(=\dfrac{1411}{115}+\dfrac{1}{2}-\dfrac{5}{27}\)
\(=\dfrac{2937}{230}-\dfrac{5}{27}\)
\(\approx12,58\)
Vậy ...
\(5\frac{27}{5}+\frac{27}{23}+0,5-\frac{5}{27}+\frac{16}{23}\)
=\(\frac{52}{5}+\frac{27}{23}+\frac{1}{2}-\frac{5}{27}+\frac{16}{23}\)
=(\(\frac{52}{5}+\frac{1}{2}\)) + (\(\frac{27}{23}+\frac{16}{23}\)) - \(\frac{5}{27}\)
=\(\frac{109}{10}+\frac{43}{23}-\frac{5}{27}\)
=12,58438003
hay \(\approx12,58\)
