\(2\sqrt{27}-6\sqrt{\frac{4}{3}}+\frac{3}{5}\sqrt{75}\\ =2.3\sqrt{3}-12.\frac{1}{\sqrt{3}}+3\sqrt{3}\\ =5\sqrt{3}\)
Lời giải chi tiết:
\( 2\sqrt {27} - 6\sqrt {\dfrac{4}{3}} + \dfrac{3}{5}\sqrt {75} \\ = 2.\sqrt 9 .\sqrt 3 - 6\dfrac{{\sqrt 4 }}{{\sqrt 3 }} + \dfrac{3}{5}.\sqrt {25} .\sqrt 3 \\ = 2.3\sqrt 3 - 6\dfrac{2}{{\sqrt 3 }} + \dfrac{3}{5}.5\sqrt 3 \\ = 6\sqrt 3 - \dfrac{{12}}{{\sqrt 3 }} + \dfrac{{15\sqrt 3 }}{5}\\ = 6\sqrt 3 - \dfrac{{12\sqrt 3 }}{{\sqrt 3 .\sqrt 3 }} + 3\sqrt 3 \\ = 6\sqrt 3 - 4\sqrt 3 + 3\sqrt 3 \\ = 5\sqrt 3 \)
\(\boxed{NTT}\)