Có: \(\left\{{}\begin{matrix}h=\frac{1}{2}gt_1^2=4,9t_1^2\left(1\right)\\h=330t_2\left(2\right)\end{matrix}\right.\)
Lại có: t1+t2 =6 => t2 =6-t1
(1) =(2) => \(4,9t_1^2=330t_2\)
\(\Leftrightarrow4,9t^2_1=330\left(6-t_1\right)\)
\(\Leftrightarrow4,9t_1^2=1980-330t_1\)
=> \(t_1\approx5,54s\)
Chiều sâu của hang là: \(h=\frac{1}{2}.9,8.5,54^2\approx150,39m\)