\(2\ge\frac{x}{2}+\frac{8}{y}\ge2\sqrt{\frac{8x}{2y}}=4\sqrt{\frac{x}{y}}\Rightarrow\frac{x}{y}\le\frac{1}{4}\Rightarrow\frac{y}{x}\ge4\)
\(A=\frac{x}{y}+\frac{y}{16x}+\frac{31}{16}.\frac{y}{x}\ge2\sqrt{\frac{xy}{16xy}}+\frac{31}{16}.4=\frac{33}{4}\)
Dấu "=" xảy ra khi \(\left\{{}\begin{matrix}x=2\\y=8\end{matrix}\right.\)