Question

tất cả giá trị x thỏa mãn 4 x ^2 ( x + 2021) - x - 2021=0

Answer 1

\(\Leftrightarrow4x^2\left(x+2021\right)-\left(x+2021\right)=0\\ \Leftrightarrow\left(x+2021\right)\left(4x^2-1\right)=0\\ \Leftrightarrow\left(2x-1\right)\left(2x+1\right)\left(x+2021\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=\dfrac{1}{2}\\x=-\dfrac{1}{2}\\x=-2021\end{matrix}\right.\)

Answer 2

Lời giải:

$4x^2(x+2021)-x-2021=0$

$\Leftrightarrow 4x^2(x+2021)-(x+2021)=0$

$\Leftrightarrow (x+2021)(4x^2-1)=0$

$\Leftrightarrow (x+2021)(2x-1)(2x+1)=0$

$\Rightarrow x+2021=0$ hoặc $2x-1=0$ hoặc $2x+1=0$

$\Leftrightarrow x=-2021$ hoặc $x=\pm \frac{1}{2}$