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\(4-2\sqrt{15} <0\)
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Giai pt
1,sqrt{x+8-6sqrt{x-1}}4
2,sqrt{x+6-2sqrt{x+2}}+sqrt{x+11-6sqrt{x+2}}1
3,sqrt{x-3-2sqrt{x-4}}+sqrt{x-4sqrt{x-4}}1
4,sqrt{x-2+sqrt{2x+5}}+sqrt{x+2+3sqrt{2x-5}}dfrac{7}{2}
5,sqrt{2x+4+6sqrt{2x-5}}+sqrt{2x-4-2sqrt{2x-5}}4
6,sqrt{dfrac{1}{4}x^2+x+1}-sqrt{6-2sqrt{5}}0
7,x+sqrt{x+dfrac{1}{2}}+sqrt{x+dfrac{1}{4}}2
8,sqrt{left(x-1right)+4-4sqrt{x-1}}+sqrt{x-1-6sqrt{x-1+9}}1
9,sqrt{x+2sqrt{x-1}}+sqrt{x-2sqrt{x-1}}dfrac{x+3}{2}
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Giai pt
1,\(\sqrt{x+8-6\sqrt{x-1}}\)=4
2,\(\sqrt{x+6-2\sqrt{x+2}}\)+\(\sqrt{x+11-6\sqrt{x+2}}\)=1
3,\(\sqrt{x-3-2\sqrt{x-4}}\)+\(\sqrt{x-4\sqrt{x-4}}\)=1
4,\(\sqrt{x-2+\sqrt{2x+5}}\)+\(\sqrt{x+2+3\sqrt{2x-5}}\)=\(\dfrac{7}{2}\)
5,\(\sqrt{2x+4+6\sqrt{2x-5}}\)+\(\sqrt{2x-4-2\sqrt{2x-5}}\)=4
6,\(\sqrt{\dfrac{1}{4}x^2+x+1}\)-\(\sqrt{6-2\sqrt{5}}\)=0
7,x+\(\sqrt{x+\dfrac{1}{2}}\)+\(\sqrt{x+\dfrac{1}{4}}\)=2
8,\(\sqrt{\left(x-1\right)+4-4\sqrt{x-1}}+\sqrt{x-1-6\sqrt{x-1+9}}\)=1
9,\(\sqrt{x+2\sqrt{x-1}}\)+\(\sqrt{x-2\sqrt{x-1}}\)=\(\dfrac{x+3}{2}\)
1.\(\sqrt{\frac{\left(1-x\right)}{x}}=\frac{\left(2x+x^2\right)}{1+x^2}\)
2. 3(2-\(\sqrt{x+2}\))=2x+\(\sqrt{x+6}\)
3. \(\sqrt[3]{x+2}+\sqrt[3]{x+1}=\sqrt[2]{2x^2}+\sqrt[3]{2x^2+1}\)
4. \(\sqrt[3]{x+24}+\sqrt{12-x}=6\)
Toán 10 ạ, giúp em với
Giải phương trình:
1) \(\sqrt{x+3-4\sqrt{x-1}}+\sqrt{x+8-6\sqrt{x-1}}=1\)
2) \(\sqrt{x+2+3\sqrt{2x-5}}+\sqrt{x-2-\sqrt{2x-5}}=2\sqrt{2}\)
2 ( 2x+1 ) \sqrt{ x+1 } + ( 4-x ) \sqrt{ 2-2x } = 6 \sqrt{ x ^{ 2 } +2 }
Tìm x:
a.\(\sqrt{4-\sqrt{4+x}}=x\)
b.\(4\left(\sqrt{x-1}-3\right)x^2+\left(13\sqrt{x+1}-8\right)x-4\sqrt{x-1}-3=0\)
c.\(\sqrt{2x-3}+2\sqrt{x-3}\ge3\sqrt[4]{2x^2+x-6}\)
\(4\sqrt{1-a}=a+6-3\sqrt{1-a^2}+5\sqrt{1+a}\)
26 tháng 11 2019 lúc 16:40
Giải phương trình :
1) \(\sqrt{x+10}-\sqrt{3-4x}=2\sqrt{x+2}\)
2)\(\sqrt{1-\sqrt{x^4-x^2}}=x-1\)
\(\frac{1}{\sqrt{x+1}+1}+\frac{1}{\sqrt{x+4}+2}+\frac{1}{\sqrt{x+9}+3}+\frac{1}{\sqrt{x+16}+4}=\frac{1}{\sqrt{x+100}+10}\)
tìm x=?
\(\sqrt{\frac{6}{2-x}}+\sqrt{\frac{10}{3-x}}=4\)
help me
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