Đk: ...
\(\sqrt{4x+8}-\sqrt{2x-1}+\sqrt{9x+18}=0\)
\(\Leftrightarrow\sqrt{4\left(x+2\right)}-\sqrt{2x-1}+\sqrt{9\left(x+2\right)}=0\)
\(\Leftrightarrow2\sqrt{x+2}-\sqrt{2x-1}+3\sqrt{x+2}=0\)
\(\Leftrightarrow5\sqrt{x+2}=\sqrt{2x-1}\)
\(\Leftrightarrow25x+50=2x-1\)
\(\Leftrightarrow23x=-51\Leftrightarrow x=-\dfrac{51}{23}\)
**đối chiếu đk, thử lại nghiệm, ghi (N) hoặc (L) rồi kết luận)
Tìm x biết:
a.\(\sqrt{18x}+2\sqrt{8x}-3\sqrt{2x}=12\)
b.\(\sqrt{9x+18}+2\sqrt{36x+72}-\sqrt{4x+8}=26\)
c.\(\sqrt{\left(x-2\right)^2}=10\)
d.\(\sqrt{9x^2-6x+1}=15\)
e.\(\sqrt{3x+4}=3x-8\)
Giải các phương trình sau:
a. \(\sqrt{25x+75}+3\sqrt{x-2}=2\sqrt{x-2}+\sqrt{9x-18}\)
b. \(\sqrt{\left(2x-1\right)^2}=4\)
c. \(\sqrt{\left(2x+1\right)^2}=3x-5\)
d. \(\sqrt{4x-12}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
Bài 1: Tìm x, biết
a)\(2\sqrt{9x-27}-\dfrac{1}{5}\sqrt{25x-75}-\dfrac{1}{7}\sqrt{49x-147}=20\)
b) \(\sqrt{9x+18}-5\sqrt{x+2}+\dfrac{4}{5}\sqrt{25x+50}=6\)
c)\(\sqrt{16x-16}-\sqrt{9x-9}+\sqrt{4x-4}+\sqrt{x-1}=8\)
d) \(\sqrt{x+2\sqrt{x-1}}-\sqrt{x-2\sqrt{x-1}}=2\)
giải phương trình
a)\(\sqrt{2x}-\sqrt{98}=0\)
b)\(\sqrt{2x}=\sqrt{8}\)
c)\(\sqrt{5x^2}=\sqrt{20}\)
d)\(\sqrt{2x}-3\sqrt{8x}+4\sqrt{32x}=52\)
e)\(3\sqrt{x-1}+2\sqrt{4x-4}-3\sqrt{9x-9}=-6\)
f)\(\sqrt{x-1}+\sqrt{4x-4}-\sqrt{25x-25}+2=0\)
g)\(\sqrt{9x^2+18}+2\sqrt{x^2+2}-\sqrt{25x^2+50+3}=0\)
h)\(\sqrt{x-1}=\sqrt{3}\)
k)\(\sqrt{9x^2-6x+1}=3\)
l)\(\sqrt{2x-1}=2\)
m)\(\sqrt{x+2}=\sqrt{3-x}\)
n)\(\sqrt{4x^2}-4x+1=\sqrt{7-4\sqrt{3}}+\sqrt{7+4\sqrt{3}}\)
Tìm x:
\(\sqrt{9x+18}-0,5\sqrt{4x+8}-\dfrac{4}{5}\sqrt{25x+50}=-10\)
Giải các phương trình sau:
a. \(\sqrt{25x+75}+2\sqrt{9x+27}=5\sqrt{x+3}+18\)
b. \(\sqrt{4x-8}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+8\)
a)\(\sqrt{4x-12}+\sqrt{9x-27}-4\sqrt{x-3}+3-x\)
b) \(\sqrt{25x-25}-3\sqrt{x-2}=2+4\sqrt{x+3}+\sqrt{9x-18}\)
c) \(\sqrt{49x-98}-14\sqrt{\dfrac{x-2}{49}}=\sqrt{9x-18}+18\)
d) \(\sqrt{x+\sqrt{2x-1}}+\sqrt{x-\sqrt{2x-1}}=\sqrt{2}\)
giúp mk vs
\(6x^2+2x+\sqrt[3]{3x^2+x+4}-10=0\)
\(x+1+\sqrt{x^24x+1}=3\sqrt{x}\)
\(x^2+2x\sqrt{x^2+4x+1}=3\sqrt{x}\)
\(\sqrt{x+8}+\dfrac{9x}{\sqrt{x+8}}-6\sqrt{x}=0\)
Bài 1: giải p.trình
a,\(\sqrt{x^2-4x+4}=1\)
b,\(\sqrt{1-4x+4x^2}=5\)
c,\(\sqrt{a\left(1-2x+x^2\right)}-6=0\)
d,\(\sqrt{9x^2}=2x+1\)
e,\(\sqrt{9-6x+x^2}=x\)
