Question

\(\sqrt{3x-5}=-2x+1\)

Answer 1

\(\Leftrightarrow\left\{{}\begin{matrix}-2x+1\ge0\\3x-5=\left(-2x+1\right)^2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\le\frac{1}{2}\\3x-5=4x^2-4x+1\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\le\frac{1}{2}\\4x^2-7x+6=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\le\frac{1}{2}\\\left(2x-\frac{7}{4}\right)^2=-\frac{47}{16}\left(VL\right)\end{matrix}\right.\)

Vậy pt vô nghiệm