Question

\(\sqrt{3-2\sqrt{2}}\) - \(\sqrt{3+2\sqrt{2}}\)

Answer 1

Lời giải:
$\sqrt{3-2\sqrt{2}}-\sqrt{3+2\sqrt{2}}=\sqrt{2-2\sqrt{2}+1}-\sqrt{2+2\sqrt{2}+1}$

$=\sqrt{(\sqrt{2}-1)^2}-\sqrt{(\sqrt{2}+1)^2}$

$=|\sqrt{2}-1|-|\sqrt{2}+1|=\sqrt{2}-1-(\sqrt{2}+1)=-2$

Answer 2

\(=\sqrt{2}-1-\sqrt{2}-1=-2\)