\(\sqrt{19-6\sqrt{2}}=\sqrt{\left(3\sqrt{2}-1\right)^2}=3\sqrt{2}-1\)
\(\sqrt{19-6\sqrt{2}}\)
\(=\sqrt{18-2\sqrt{18}+1}\)
\(=\sqrt{\left(\sqrt{18}-1\right)^2}\)
\(=\sqrt{18}-1\)
\(\sqrt{19-6\sqrt{2}}\)
\(\sqrt{19-6\sqrt[]{2}}\)
a.\(\sqrt{\frac{289+4\sqrt{72}}{16}}+\sqrt{\frac{129}{16}+\sqrt{2}}\)
b. \(\sqrt{16-6\sqrt{7}}+\sqrt{10-2\sqrt{21}}\)
c. \(\sqrt{28+\sqrt{300}}+\sqrt{19-\sqrt{192}}\)
Tính :\(\sqrt{19-6\sqrt{ }2}\)
\(\sqrt{12+2\sqrt{ }3}\) Giúp nhanh dùm mình với ạ ''))
18 - 6\(\sqrt{10}\)
19 + 8\(\sqrt{3}\)
27 + 10\(\sqrt{2}\)
28 + 12\(\sqrt{2}\)
Bài 19: Thực hiện phép tính
a) \(\sqrt{3+2\sqrt{2}}+\sqrt{3-2\sqrt{2}}\)
b) \(\left(5\sqrt{2}+3\sqrt{3}\right).\left(2\sqrt{2}-\sqrt{3}\right)\)
1)\(\sqrt{4+\sqrt{10+2\sqrt{5}}}+\sqrt{4-\sqrt{10+2\sqrt{5}}}\)
2)\(\sqrt{35+12\sqrt{6}}-\sqrt{35-12\sqrt{6}}\)
3)\(\left(4+\sqrt{15}\right)\left(\sqrt{10}-\sqrt{6}\right)\sqrt{4-\sqrt{15}}\)
a) \(\sqrt{5+2\sqrt{6}}-\sqrt{3-2\sqrt{2}}\)
b) \(\sqrt{11+6\sqrt{2}}-\sqrt{18+8\sqrt{2}}\)
c) \(\sqrt{2}\sqrt{2-\sqrt{3}}\left(\sqrt{3}+1\right)\)
viết thành bình phương của 1 biểu thức:
d,\(17\pm12\sqrt{2}\)
e,\(9\pm4\sqrt{5}\)
f,\(19\pm8\sqrt{3}\)
