\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}=3-2\sqrt{2}+3+2\sqrt{2}=6\)
\(\sqrt{17-3\sqrt{32}}+\sqrt{17+3\sqrt{32}}=\sqrt{\left(3-2\sqrt{2}\right)^2}+\sqrt{\left(3+2\sqrt{2}\right)^2}=3-2\sqrt{2}+3+2\sqrt{2}=6\)
I.
1, \(\sqrt{8}-3\sqrt{32}+\sqrt{72}\)
2, \(6\sqrt{12}-2\sqrt{48}+5\sqrt{75}-7\sqrt{108}\)
3, \(\sqrt{20}+3\sqrt{45}-6\sqrt{80}-\dfrac{1}{3}\sqrt{125}\)
4, \(2\sqrt{5}-\sqrt{125}-\sqrt{80}\)
5, \(3\sqrt{2}-\sqrt{8}+\sqrt{50}-4\sqrt{32}\)
a, \(\sqrt{9-\sqrt{ }17}\)x \(\sqrt{9+\sqrt{ }17}\)
b, \(\sqrt{7+4\sqrt{ }3}\)
B1:Tính
a) \(\sqrt{11}.\sqrt{1100}\)
b) \(\frac{\sqrt{10}-\sqrt{15}}{\sqrt{8}-\sqrt{12}}\)
c) \(\frac{\sqrt{15}-\sqrt{5}}{\sqrt{3}-1}\)
d) \(\sqrt{9-\sqrt{17}}.\sqrt{9+\sqrt{17}}\)
e) \((\sqrt{3-\sqrt{5}}+\sqrt{3+\sqrt{5}})^2\)
Mn giúp mình với ạ!!!
Chứng minh :
a) \(\sqrt{9-\sqrt{17}}.\sqrt{9+\sqrt{17}}=8\)
b) \(2\sqrt{2}\left(\sqrt{3}-2\right)+\left(1+2\sqrt{2}\right)^2-2\sqrt{6}=9\)
Bài 1 : Rút gọn
a) \(\frac{\sqrt{6}+\sqrt{16}}{2\sqrt{3}+\sqrt{28}}\)
b) \(\frac{\sqrt{2}+\sqrt{3}+\sqrt{6}+\sqrt{8}+\sqrt{16}}{\sqrt{2}+\sqrt{3+\sqrt{4}}}\)
Bài 2: Chứng minh
a)\(\sqrt{9-\sqrt{17}}-\sqrt{9+\sqrt{17}}=8\)
b)\(2\sqrt{2}\left(\sqrt{3}-2\right)+\left(1+2\sqrt{2}\right)^2-2\sqrt{6}=9\)
tính
\(\frac{3}{4}\sqrt{2}\left(\frac{4}{3}\sqrt{8}-\frac{2}{3}\sqrt{32}-4\sqrt{18}\right)\)
\(\sqrt{6,5+\sqrt{ }12}-\sqrt{6.5-\sqrt{12}+2\sqrt{6}}\)
\(\sqrt{94-42\sqrt{5}-\sqrt{94+42\sqrt{5}}}\)
\(\sqrt{50}-2\sqrt{72}-3\sqrt{2}+\sqrt{32}\)
\(\left(2\sqrt{5}-\sqrt{125}+\sqrt{80}\right)\sqrt{5}\)
\(\left(5\sqrt{2}-3\sqrt{32}+\sqrt{200}\right)\sqrt{8}\)
(\(\sqrt{45}+\frac{1}{2}\sqrt{20}-4\sqrt{5}-\sqrt{\left(1-15^2\right)}\))\(^2 \)
\(\sqrt{9-4\sqrt{5}-3\sqrt{80}}\)
Giúp mình với ạ ! Mai mình nộp rồi
\(\sqrt{9-\sqrt{ }17}\) - \(\sqrt{9+\sqrt{ }17}\)
Rút gọn biểu thức:
a. A= (\(\sqrt{5-2\sqrt{6}}+\sqrt{2}\) ) \(\sqrt{3}\)
b. B= \(\sqrt{4+2\sqrt{3}}+\sqrt{5+2\sqrt{6}}+\sqrt{2}\)
c. C= \(2+\sqrt{17-4\sqrt{9+4\sqrt{5}}}\)