Ta có: \(\sqrt{16+225}=\sqrt{241}< \sqrt{361}=19=4+15=\sqrt{16}+\sqrt{225}\)
Vậy \(\sqrt{16+225}< \sqrt{16}+\sqrt{225}\)
Ta có:\(\sqrt{16+225}\) =\(\sqrt{241}\) \(\approx15,5241\)
\(\sqrt{16}+\sqrt{225}=4+15=19\)
15,5241<19
hay \(\sqrt{16+225}< \sqrt{16}+\sqrt{225}\)
Vậy \(\sqrt{16+225}< \sqrt{16}+\sqrt{225}\)