Ta có: \(A=\frac{1946}{1986}=\frac{1986-40}{1986}=1-\frac{40}{1986}\)
\(B=\frac{1968}{2008}=\frac{2008-40}{2008}=1-\frac{40}{2008}\)
Ta có: \(\frac{40}{1986}>\frac{40}{2008}\)
\(\Rightarrow-\frac{40}{1986}< -\frac{40}{2008}\)
\(\Rightarrow-\frac{40}{1986}+1< \frac{-40}{2008}+1\)
hay A<B