Đặt\(A=3^{2012}-3^{2011}+3^{2010}-3^{2009}+...+3^2-3+1\)
\(\Rightarrow3A=3^{2013}-3^{2012}+3^{2011}-3^{2010}+...+3^3-3^2+3\)
\(\Rightarrow A+3A=\left(3^{2012}-3^{2011}+3^{2010}-3^{2009}+...+3^2-3+1\right)+\left(3^{2013}-3^{2012}+3^{2011}-3^{2010}+...+3^3-3^2+3\right)\)\(\Rightarrow4A=3^{2013}+1>1\Rightarrow A>\frac{1}{4}\)
Vậy \(A>\frac{1}{4}\)