a) Có: 290=25.18=(25)18=3218
536=52.18=2518
mà 32>25=> 3518>2518<=> 290> 536
b)Có 227=23.9=89
318=32.9=99
c) Có (x-1)5=-32
<=> (x-1)5=-25
<=> x-1=-2
<=> x=-1
bài 1 :
Ta có : 290 = 25.18 = ( 25 )18 = 3218
\(5^{36}=5^{2.18}=\left(5^2\right)^{18}=25^{18}\)
Vì 32 > 25 => \(32^{18}>25^{18}\) hay \(2^{90}>5^{36}\)
Bài 2 :
\(2^{27}=2^{3.9}=\left(2^3\right)^9=8^9\)
\(3^{18}=3^{2.9}=\left(3^2\right)^9=9^9\)
Bài 3 :
\(\left(x-1\right)^5=-32\)
\(\left(x-1\right)^5=-2^5\)
\(x-1=-2\)
\(x=-2+1\)
\(x=-1\)