\(\frac{21}{25}=\frac{1}{25}+\frac{20}{25}>\frac{20}{27}\)
\(=\frac{60}{81}>\frac{20}{29}\)
\(=\frac{19}{29}\)
Ta có:\(\frac{60}{81}\)=\(\frac{20}{27}\)
Quy đồng:
25=52
27=33
29=29
BCNN(25;27;29)=19575
\(\frac{21}{25}=\frac{21.783}{25.783}=\frac{16443}{19575}\)
\(\frac{20}{27}=\frac{20.725}{27.725}=\frac{14500}{19575}\)
\(\frac{19}{29}=\frac{19.675}{29.675}=\frac{12825}{19575}\)
Vì 12825<14500<16443=>\(\frac{19}{29}< \frac{20}{27}< \frac{21}{25}\)
Hay \(\frac{19}{29}\)\(< \frac{60}{81}< \frac{21}{25}\)