Question

rút gọn giúp e vs ạ

Answer 1

Với `x > 0,x \ne 1` có:

    `1/[x+\sqrt{x}]+[2\sqrt{x}]/[x-1]-1/[x-\sqrt{x}]`

`=[\sqrt{x}-1+2x-\sqrt{x}-1]/[\sqrt{x}(\sqrt{x}-1)(\sqrt{x}+1)]`

`=[2x-2]/[\sqrt{x}(x-1)]`

`=[2(x-1)]/[\sqrt{x}(x-1)]`

`=2/\sqrt{x}`