Ta có: A = (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+\sqrt{12}+\sqrt{18-\sqrt{128}}}}}\)
= (\(\sqrt{3}-1)\)\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+\sqrt{16-8\sqrt{2}+2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+\sqrt{\left(4-\sqrt{2}\right)^2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+\sqrt{\left(4-\sqrt{2}\right)^2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+4-\sqrt{2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{2+2\sqrt{3}+4-\sqrt{2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+2\sqrt{2}.\sqrt{3-\sqrt{6+2\sqrt{3}-\sqrt{2}}}}\)
= (\(\sqrt{3}-1\))\(\sqrt{6+\sqrt{24-8\sqrt{6+2\sqrt{3}-\sqrt{2}}}}\)
