Question

Quy đồng mẫu thức hai phân thức \(\dfrac{1}{x^2+x}\) và \(\dfrac{1}{x^2-x}\).

Answer 1

MTC=x(x+1)(x-1)

\(\dfrac{1}{x^2+x}=\dfrac{1}{x\left(x+1\right)}=\dfrac{x-1}{x\left(x+1\right)\left(x-1\right)}\)

\(\dfrac{1}{x^2-x}=\dfrac{1}{x\left(x-1\right)}=\dfrac{x+1}{x\left(x-1\right)\left(x+1\right)}\)