Câu hỏi của Dương Thanh Ngân

Question

Phân tích thành nhân tử:

a/$5x+5y=............$

b/$x^3+x^2+x=............$

c/$2x\left(x-y\right)+4\left(x-y\right)=.........$

d/$15x\left(x-2\right)+9y\left(2-x\right)$

Trần Thanh Phương · Accepted Answer

a) $5x+5y=5\left(x+y\right)$

b) $x^3+x^2+x=x\left(x^2+x+1\right)$

c) $2x\left(x-y\right)+4\left(x-y\right)=\left(x-y\right)\left(2x+4\right)=2\left(x-y\right)\left(x+2\right)$

d) $15\left(x-2\right)+9y\left(2-x\right)=\left(x-2\right)\left(15-9y\right)=3\left(x-2\right)\left(5-3y\right)$Câu trả lời: a) $5x+5y=5\left(x+y\right)$

b) $x^3+x^2+x=x\left(x^2+x+1\right)$

c) $2x\left(x-y\right)+4\left(x-y\right)=\left(x-y\right)\left(2x+4\right)=2\left(x-y\right)\left(x+2\right)$

d) $15\left(x-2\right)+9y\left(2-x\right)=\left(x-2\right)\left(15-9y\right)=3\left(x-2\right)\left(5-3y\right)$

Kiêm Hùng · Answer

$a.5x+5y$

$\Leftrightarrow5\left(x+y\right)$

$b.x^3+x^2+x$

$\Leftrightarrow x\left(x^2+x+1\right)$

$c.2x\left(x-y\right)+4\left(x-y\right)$

$\Leftrightarrow\left(2x+4\right)\left(x-y\right)$

$\Leftrightarrow2\left(x+2\right)\left(x-y\right)$

$d.15x\left(x-2\right)+9y\left(2-x\right)$

$\Leftrightarrow\left(15x-9y\right)\left(x-2\right)$

$\Leftrightarrow3\left(5x-3y\right)\left(x-2\right)$Câu trả lời: $a.5x+5y$