Question

Phân tích đa thức thành nhân tử: \(x^8+3x^4+4\)

Answer 1

\(x^8+3x^4+4\)

\(=x^8+4x^4+4-x^4\)

\(=\left(x^4-2\right)^2-x^4\)

\(=\left(x^4-x^2-2\right)\left(x^4-x^2-2x^2-2\right)\)

\(=\left(x^2-2\right)\left(x^2+1\right)\left(x^2-1\right)\left(x^2+2\right)\)

\(=\left(x-1\right)\left(x+1\right)\left(x^2-2\right)\left(x^2+1\right)\left(x^2+2\right)\)

Answer 2

x⁸+3x⁴+4=(x⁸+4x⁴+4)-x⁴=(x⁴+2)²-x⁴=(x⁴+2-x²)(x⁴+2+x²)

Answer 3

\(x^8+3x^4+4\)

\(=\left(x^4+x^2+2\right)\left(x^4-x^2+2\right)\)